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20% of a radio active element disintegrates in 1hr. The percentage of the radio active element disintegrated in 2hrs will be

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36%

64%

60%

40%

answer is A.

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Detailed Solution

$W = \frac{W_{0}}{2^{n}}$ . Initial amount W₀ , after one hour amount of remaining sample =80% W₀ ; $W_{1} = \frac{80}{100} W_{0}$

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