Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8

Q.

200 Mev energy is released when one nucleus of 235U undergoes fission. Find the number of fissions per second required for producing a power of 1 mega watt.

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

3.125 × 1014

b

3.125 × 1015

c

3.125 × 1016

d

3.125 × 1013

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

E = 200Mev
=200×106×1.6×1019=32×1012JP=nEt106=n×32×10121n=10632×1012=3.125×1016

Watch 3-min video & get full concept clarity

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
200 Mev energy is released when one nucleus of 235U undergoes fission. Find the number of fissions per second required for producing a power of 1 mega watt.