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Q.

200 ml of 2 M Phosphorous acid completely neutralizes ‘X’ ml of 2 M KOH solution. The value of ‘X’ is

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a

100

b

400

c

200

d

800

answer is A.

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Detailed Solution

$V_{a} N_{a} = V_{b} N_{b} 200 (2) 2 = V_{2} (2) 1; V_{2} = 400 ml;$

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