200 ml of an aqueous solution of glucose C6H12O6 has molarity of 0.01M. Which of the following operations can be done to this solution so as to decrease molarity to 0.015 M?

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200 ml of an aqueous solution of glucose $(C_{6} H_{12} O_{6})$ has molarity of 0.01M. Which of the following operations can be done to this solution so as to decrease molarity to 0.015 M?

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Add 0.18 g glucose to solution without changing its volume

Evaporate 50 ml water from this solution

Add 50 ml water to this solution

None of the above

answer is B.

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Detailed Solution

Add 0.18 g glucose to solution without changing its volume satisfy the given condition for decreased molarity to 0.015 M. It can be seen in the below calculation.

$\frac{0.2 \times 0.01 + \frac{0.18}{180}}{0.2} = 0.015 M$

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