200 ml of an aqueous solution of glucose $\left({\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{O}}_6\right)$ has molarity of 0.01M. Which of the following operations can be done to this solution so as to decrease molarity to 0.015 M?

Add 0.18 g glucose to solution without changing its volume satisfy the given condition for decreased molarity to 0.015 M. It can be seen in the below calculation.

$\frac{0.2\times 0.01+\frac{0.18}{180}}{0.2}=0.015\mathrm{M}$