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Q.

200 ml of $O_{3}, O_{2}$ mixture was passed through turpentine oil and reduction of 36 ml took place in volume. If 200 ml of this mixture is heated then what will be increase in volume in ml?

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Detailed Solution

Volume absorb in turpentine $= 36 m l$
i.e $O_{3} = 36 m l$

   $O_{2} = 200 - 36 = 164 m l$
   $2 O_{3} \to 3 O_{2}$
   $2 V 3 V$
   $1 V 3 / 2 V$

$36 V \frac{3}{2} \times 36 = 54 m l$
Total vol of oxygen $= 164 + 54 = 218 m l$

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