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Q.

200mL of 0.01MHCl is mixed with 400 mL of 0.01M H2SO4. The pH of the mixture is____.

[log 2=0.3010,log 3=0.48,log 5=0.7,log 7=0.84,log 11=1.04]

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a

3.02

b

1.14

c

1.78

d

2.34

answer is B.

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Detailed Solution

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H+=0.01×200+2×0.01×400600=0.01+2×0.01×23=0.01+0.043=53×102pH=logH+=log53×102=log53+log102=[log5log32]=0.7+0.48+2=2.480.7=1.78

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