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Q.

20ml of 0.1M acetic acid is mixed with 50ml of potassium acetate. Ka of acetic acid =1.8× 10-5 at 27°C. The concentration of potassium acetate if pH of the mixture is 4.8

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a

0.1M

b

0.02M

c

0.4M

d

0.04M

answer is B.

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Detailed Solution

So we can say that concentration of potassium acetate is x.

According to Henderson's equation,

pH=pKa+log[ salt]  [acid ]

 4.8=-log1.8×10-5+logx×5020×0.1M

4.8=4.74+log25x

 or log25x=0.06

 25 x=1.148

 x=0.045M

Therefore, the correct option is (B).

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20ml of 0.1M acetic acid is mixed with 50ml of potassium acetate. Ka of acetic acid =1.8× 10-5 at 27°C. The concentration of potassium acetate if pH of the mixture is 4.8