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21.4 mg of salt XCl is completely dissolved in some amount of water to form 2 litre of a solution. If $p H$ of the following solution is observed to be 5 & the salt in solid state forms rock salt structure with ionic radii of $X^{+} = 0.8 A^{0} & C l^{-} = 1.7 A^{0}$ then calculate density of the solid crystal in terms of $g m / c m^{3}$ .[Data: $N_{A} = 6 \times 10^{23}, K_{b} (X O H) = 10^{- 9}$ ]

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answer is 57.

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Detailed Solution

(molecular weight=1070)

$\frac{21.4 \times 10^{- 3}}{M \times 2} = c o n c . o f s a l t s o l u t i o n$

$P^{H} = 7 - \frac{1}{2} [\log c - \log K_{b}]$

$5 = 7 - \frac{1}{2} [\log \frac{21.4 \times 10^{- 3}}{2 M} + 9]$

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