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Q.

2.2 g of nitrous oxide N2O gas is cooled at a constant pressure of 1 atm from 310 K to 270 K causing the compression of the gas from 217.1 mL to 167.75 mL. The change in internal energy of the process, ΔU is ‘-x’ J. The value of 'x ' is_________. [nearest integer]

 (Given: atomic mass of N=14gmol1 and of O=16gmol1.  Molar heat capacity of N2O is 100JK1mol1 ) 

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answer is 195.

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Detailed Solution

N2Omoles=2.244=120ΔH=nCpΔT=120×100(40)=200JΔU=qp+ww=Pext. ΔVW=1(167.75217.1)1000×101.3Jw=+5JΔU=200+5=195J

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