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Q.

ω+2ω2+3ω3+......90ω90=

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a

301-ω

b

451-ω

c

901-ω

d

0

answer is A.

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Detailed Solution

  w+2w2+3w3+....+90w30w=w4=w7=....=w88w2=w5=w8=...=w89w3=w6=             =w90 =w(1+4+7+...+88)+w2(2+5+...+89)+w3(3+6+...+90) =w·302(1+88)+w2·302(2+89)+w3(3+90)×302 =15(89w+91w2+93) =15(89(1+w+w2)+2w2+4) =15(2(1+w2)+2) =15(-2w+2) =30(1-w)

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