24 cells, each of emf 1.5V and internal resistance $2 Ω$ are to be connected in order to send the maximum current through a $12 Ω$ external resistor. Then,

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The current in each cell is $0.75 A$

Potential difference across $12 Ω$ resistor is $4.5 V$

The correct arrangement of cells will be 2 rows of 12 cells connected in parallel.

The current in each row is $0.375 A$

answer is A, B.

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Detailed Solution

$x y = 24$

In series= $2 x$

$\begin{array}{l} \frac{1}{r} = \frac{1}{2 x} + \frac{1}{2 x} \\ \frac{2 x}{y} = 6 \\ x y = 24 \\ x = 12, y = 2 \end{array}$

2 rows of 12 cells in series

ii) $I = \frac{T o t a l c m f}{T o t a l r e s i s \tan c e}$

$\begin{array}{l} \Rightarrow \frac{1.5 \times 12}{12 + 12} = \frac{18}{24} = 0.75 \\ \Rightarrow \frac{0.75}{2} = 0.375 A \end{array}$

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