25 g of water contain

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16.722 \times 10^{23}

atoms of Hydrogen and

8.362 \times 10^{23}

atoms of oxygen

5 \times 10^{24}

atoms of Hydrogen and

2.5 \times 10^{24}

atoms oxygen

12 \times 10^{23}

atom of Hydrogen and

6 \times 10^{23}

atom of oxygen

2.72 \times 10^{23}

atoms of Hydrogen and

8.372 \times 10^{23}

atoms oxygen

answer is D.

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Detailed Solution

Number of moles in 25g of

H_{2} O = \frac{25}{18}

= 1.388 moles.

Number of H-atoms = Number of moles of $H_{2} O \times A v o g a d r o' s n u m b e r \times 2$

$= 1.388 \times 2 \times 6.023 \times 10^{23}$

$= 16.722 \times 10^{23}$ atoms of hydrogen

Number of oxygen – atom = number of moles of $H_{2} O$ × Avogadro’s number

$= 1.388 \times 6.023 \times 10^{23}$

$= 8.362 \times 10^{23}$ atoms of oxygen.

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