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Q.

25 g ethylene glycol is present in 100 g of water. The solution is cooled to10°C. Kf for H2O is 1.86 K kg mol1. The amount of ice separated on cooling is

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a

75 g

b

 50 g

c

20 g

d

 25 g

answer is A.

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Detailed Solution

Tf=Kf×wm×1000WIn gms

10=1.86×2562×1000W

Wweight of solvent= 75 gr

wglycol remains constant on cooling; only water freezes 

 Therefore, Ice separated   =WH2o initial taken-WH2Oremaining =100-75=25 gm

 

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