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Q.

2.5 g of protein containing only glycine (C2H5NO2) is dissolved in water to make 500 mL of solution. The osmotic pressure of this solution at 300 K is found to be 5.03×103 bar . The total number of glycine units present in the protein is __________.
(Given : R = 0.083 L bar K-1 mol-1)

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answer is 330.

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Detailed Solution

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π=CRT5.03×103=C×0.083×300C=0.202×103M Moles of protein =0.202×103×0.5                     =104×1.01 1.01×104=2.5M M(molar mass of protein) =24752 No. of glycine units =2475275=330.03

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