2.5 L of a sample of gas at 27°C  and 1 bar pressure compressed to a volume of 500 mL keeping the temperature constant. The increase in pressure is

According to Boyle’s Law,${\mathrm{P}}_1{\mathrm{V}}_1={\mathrm{P}}_2{\mathrm{V}}_2$$2.5\times 1=0.5\times {\mathrm{p}}_2$

$\Rightarrow {\mathrm{p}}_2=\frac{2.5\times 1}{0.5}=5$

Increase in pressure,$\mathrm{P}={\mathrm{P}}_{\mathrm{final}}-{\mathrm{P}}_{\mathrm{initial}}$

∴ Amount of pressure to be increased ,P = 5 − 1 =4 bar