25 mL of 0.50 M ${\mathrm{H}}_2{\mathrm{O}}_2$ solution is added to 50 mL of 0.20 M ${\mathrm{KMnO}}_4$ in acid solution. Which of the following statements is true ?

$$\begin{gathered} \mathrm{M} \mathrm{eq}. \mathrm{of} {\mathrm{KMnO}}_4 = 0.2 \times 50 \times 5=50 \\ \mathrm{M} \mathrm{eq}. \mathrm{of} {\mathrm{H}}_2{\mathrm{O}}_2 = 2 \times 25 \times 0 .5 =25 \\ \mathrm{M} \mathrm{eq}. \mathrm{of} {\mathrm{KMnO}}_4 \mathrm{remaining} = \left(50-25\right)=25 \\ \mathrm{Mole} \mathrm{of} {\mathrm{KMnO}}_4 = \frac{25}{5} \times {10}^{-3} = 5 \times {10}^{-3} = 0.005 \end{gathered}$$