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Q.

25 ml of 3.0 M ${HNO}_{3}$ are mixed with 75 ml of 4.0 M ${HNO}_{3}$ . If the volumes are additive, the molarity of the final solution would be ____?

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a

3.25 M

b

3.50 M

c

3.75 M

d

4.0 M

answer is C.

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Detailed Solution

The molarity of the resultant solution is follows

$M = \frac{M_{1} V_{1} + M_{2} V_{2}}{V_{1} + V_{2}} = \frac{25 \times 3 + 75 \times 4}{100} = \frac{75 + 300}{100} = \frac{375}{100} = 3.75 M$

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