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Q.

25 mL of the given HCl solution requires 20 mL of 0.1 M sodium carbonate solution.  What is the volume of this HCl solution required to titrate 30 mL of 0.2 M aqueous NaOH solution?

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answer is 25.

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Detailed Solution

Apply law of equivalence

25×N=30×0.1×2

NHCl=30×0.225=65×0.2=1.25

For the 2nd titration

1.25×VHCl=30×0.2, VHCl=6×51.2=301.2=25 ml

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