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25.3 g of sodium carbonate, ${Na}_{2} {CO}_{3}$ is dissolved in enough water to make 250 mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ions, ${Na}^{+}$ and carbonate ions, ${CO}_{3}^{2 -}$ are respectively (Molar mass of ${Na}_{2} {CO}_{3} = 106 g {mol}^{- 1})$

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1.90 M and 1.910M

1.910 Mand 0.955 M

0.955 M and 1.910M

0.477M and0.477M

answer is B.

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Detailed Solution

Concentration of
${Na}_{2} {CO}_{3} = \frac{25 .3}{106} \times \frac{1000}{250} = 0 .955 M [{Na}^{+}] = 2 \times 0 .955 = 1 .91 M [{CO}_{3}^{2 -}] = 0 .955 M$

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