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27 similar drops of mercury are maintained at 10V each. All these spherical drops combine into a single big drop. The potential of the bigger drop is ______ times that of a smaller drop

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answer is 9.

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Detailed Solution

The potential of the bigger drop formed on combining of 'n' drops is given by $V^{'} = n^{2 / 3} V$ .

Here, n=27.

$V^{'} = 27^{\frac{2}{3}} \times V = 9 V$

where, V' - potential of bigger drop , V - potential of smaller drop

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