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Q.

28 g of  N2  gas is contained in a flask at a pressure of 10 atm and at a temperature of 570C .It is found that due to leakage in the flask, the pressure is reduced to half and the temperature reduced to 270C . The quantity of N2 gas that is leaked out is

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a

63/5 g

b

11/20 g

c

5/63 g

d

20/11 g

answer is D.

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Detailed Solution

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PV=mMRT   Pm.T   105=28m×330300  m=28×330×510×300=23115gm=775gmGas  leaked=28775=635gm

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