$2 Al (s) + 2 NaOH (aq) + 6 H_{2} O (l) ⟶ 2 A + 3 H_{2} (g)$
Here, A is

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${Na}_{2} {[Al (OH)_{4}]}^{-} (aq)$

Sodium tetrahydroxoaluminate (III)

${Na}^{+} {[Al (OH)_{4}]}^{-} (aq)$

Sodium tetrahydroxoaluminate (III)

${Na}^{+} {[Al (OH)_{6}]}^{-} (aq)$

Sodium hexahydroxoaluminate (II)

$Na {[Al (OH)_{6}]}^{-} (aq)$

Sodium hexahydroxoalunminate (III)

answer is A.

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Detailed Solution

Aluminium reacts with aqueous alkali and liberates dihydrogen.

$2 Al (s) + 2 NaOH (aq) + 6 H_{2} O (l) ⟶ 2 {Na}^{+} {[Al (OH)_{4}]}^{-} (aq) + 3 H_{2} (g)$

Sodium tetrahydroxoaluminate(III)

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