$2 C_{6} H_{5} CHO \to_{H_{2} O}^{{OH}^{-}} C_{6} H_{5} {CH}_{2} OH + C_{6} H_{5} {COO}^{-}$
Which of the following statements are correct regarding the conversion of benzaldehyde to benzyl alcohol?
(i) One hydrogen is coming from H₂O as H⁺ and another from $C_{6} H_{5} CHO$ as $H^{-}$ .
(ii) One hydrogen is coming from $H_{2} O$ as $H^{-}$ and another from $C_{6} H_{5} CHO$ as H⁺.
(iii) One hydrogen from $H_{2} O$ and another from $C_{6} H_{5} CHO$ , both in the form of H^-.
(iv) This reaction is an example of disproportionation reaction.

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

(i), (ii) and (iii)

(i) and (iv)

(ii), (iii) and (iv)

(iii) and (iv)

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

The hydrogen atom that is added to the carbonyl carbon of the aldehyde in the reduction is derived directly from the other aldehyde molecule as a hydride ion. The second hydrogen that is added to the negatively charged oxygen is coming from the solvent (consult mechanism of Cannizzaro reaction). Oxidation of one molecule of the compound at the expense of other molecule of the same compound is known as disproportionation.

Watch 3-min video & get full concept clarity