Q.

2cos5αsin2α=

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a

sin7α+sin3α

b

cos7α+cos3α

c

sin7αsin3α

d

cos7αcos3α

answer is A.

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Detailed Solution

2cos5αsin2α

=sin(5α+2α)sin(5α2α)

=sin7αsin3α

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2cos5αsin2α=