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2g of NaOH per 250 mL of solution is added to a buffer solution of buffer capacity 0.2.Then the change in pH is

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0.5

1.5

2.0

answer is B.

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Detailed Solution

$\begin{array}{l} M = \frac{W}{GMW} \times \frac{1000}{v (m l)} \\ \frac{2}{40} \times \frac{1000}{250} = \frac{1}{5} = 0.2 M \\ ϕ = \frac{dn}{{dp}^{H}} \Rightarrow 0.2 = \frac{0.2}{{dp}^{H}} \\ {dp}^{H} = \frac{0.2}{0.2} = 1 \end{array}$

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