2grams of a mixture of $N a_{2} C O_{3} a n d N a H C O_{3}$ on strong heating has suffered a mass loss of 0.62 gram. Percent weight of $N a_{2} C O_{3}$ in the given mixture is

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Detailed Solution

$2 N a H C O_{3} \to N a_{2} C O_{3} + H_{2} O + C O_{2}$

168g of $N a H C O_{3}$ on heating suffers 62g of weight loss $H_{2} O + C O_{2}$

The amount of $N a H C O_{3}$ in the given mixture = $\frac{0.62}{62} \times 168 = 1.68 g$

The amount of Na₂CO₃ in the given mixture = $2 - 1.68 = 0.32 g$

Percentage of Na₂CO₃= 0.32 $\times$ 100=32

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