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$2 H_{2} + O_{2} \to 2 H_{2} O$ . In the given equation on using 2g of hydrogen, the amount of $H_{2} O$ formed is

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9 g

18 g

36 g

54 g

answer is A.

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Detailed Solution

${2H}_{2} + O_{2} \to {2H}_{2} O$

${2 moles of H}_{2} {2 moels of H}_{2} O$

$2 \times 2 g ×? = 2×2×18$

$= \frac{2 \times 2 \times 18}{2 \times 2}$

$= 18 g$

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