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$2 H_{2} + O_{2} \to 2 H_{2} O$ In the given equation on using 4g of hydrogen, the amount of $H_{2} O$ Formed is

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36g

54g

18 g

answer is C.

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Detailed Solution

$2 H_{2} + O_{2} \to 2 H_{2} O$

2 moles of $H_{2}$ react with one mole of Oxygen to produce 2 moles of $H_{2} O$ (36g of water) In the given equation 4g of Hydrogen means 2 moles, Hence 36g of water will be formed

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