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Q.

$2Mg (s) + O_{2} (g) \to 2MgO (s)$ Above reaction attains equilibrium at $8 0^{o} C$ and 0.5 atm pressure. The equilibrium constant Kp of the reaction is:

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a

${2 atm}^{- 1}$

b

$0. {5 atm}^{- 1}$

c

$2 . {5 atm}^{- 1}$

d

$1 . {5 atm}^{- 1}$

answer is C.

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Detailed Solution

$P_{O_{2} =} 0.5 a t m, K_{P} = \frac{1}{P_{O_{2}}} = \frac{1}{0.5} = 2$

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2Mg(s) +O2(g)→ 2MgO(s) Above reaction attains equilibrium at 80oC and 0.5 atm pressure. The equilibrium constant Kp of the reaction is: