$$\begin{gathered} 2\mathrm{MCl}+{\mathrm{H}}_2{\mathrm{SO}}_4\to {\mathrm{M}}_2{\mathrm{SO}}_4+2\mathrm{HCl} \\ 2\mathrm{MF}+{\mathrm{H}}_2{\mathrm{SO}}_4\to {\mathrm{M}}_2{\mathrm{SO}}_4+2\mathrm{HF} \\ 2\mathrm{MI}+{\mathrm{H}}_2{\mathrm{SO}}_4\to {\mathrm{M}}_2{\mathrm{SO}}_4+2\mathrm{HI} \end{gathered}$$

This reaction is not favoured in forward direction due to the formation of $\mathrm{HI}$.

$2{\mathrm{MNO}}_3+{\mathrm{H}}_2{\mathrm{SO}}_4\to {\mathrm{M}}_2{\mathrm{SO}}_4+2{\mathrm{HNO}}_3$

Thus, 1,2 and 4 are favoured.

Hence, option (D) is correct.