2NaZ+H2SO4(conc.)→ Na2SO4+2HZ. Z cannot be

2NaI+H2SO4(conc.)→ 2HI+Na2SO42HI+H2SO4(conc.)→ I2+2H2O+SO2Conc. H2SO4 oxidizes HI to I2

2NaZ+H2SO4(conc.)→ Na2SO4+2HZ. Z cannot be

2NaI+H2SO4(conc.)→ 2HI+Na2SO42HI+H2SO4(conc.)→ I2+2H2O+SO2Conc. H2SO4 oxidizes HI to I2

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$2 N a Z + H_{2} S O_{4} (c o n c .) \overset{}{\to} N a_{2} S O_{4} + 2 H Z .$ Z cannot be

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$H C l$

$H F$

$H N O_{3}$

$H I$

answer is D.

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$2 N a I + H_{2} S O_{4} (c o n c .) \overset{}{\to} 2 H I + N a_{2} S O_{4}$

$2 H I + H_{2} S O_{4} (c o n c .) \overset{}{\to} I_{2} + 2 H_{2} O + S O_{2}$

$C o n c . H_{2} S O_{4} o x i d i z e s H I t o I_{2}$

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2NaZ+H2SO4(conc.)→ Na2SO4+2HZ. Z cannot be

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$2 N a Z + H_{2} S O_{4} (c o n c .) \overset{}{\to} N a_{2} S O_{4} + 2 H Z .$ Z cannot be