2NO2+1/2O2→N2O5 If the rate of disappearance of NO2 is ‘x’ M min-1. Rate w.r.t O2 is___ and rate w.r.t to N2O5

−12dNO2d+=−2dO2dt=+dN2O5dtgiven −dNO2d+=xRate w.r.t NO2 is =x2Rate w.r.t O2=x2Rate w.r.t N2O5=x2

2NO2+1/2O2→N2O5 If the rate of disappearance of NO2 is ‘x’ M min-1. Rate w.r.t O2 is___ and rate w.r.t to N2O5

−12dNO2d+=−2dO2dt=+dN2O5dtgiven −dNO2d+=xRate w.r.t NO2 is =x2Rate w.r.t O2=x2Rate w.r.t N2O5=x2

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$2 N O_{2} + 1 / 2 O_{2} \to N_{2} O_{5}$ If the rate of disappearance of NO₂ is ‘x’ M min^-1. Rate w.r.t O₂ is___ and rate w.r.t to $N_{2} O_{5}$

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$\frac{x}{2}, \frac{x}{2}$

$\frac{x}{4}, \frac{x}{2}$

$x, x$

$\frac{x}{2}, x$

answer is C.

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Detailed Solution

$- \frac{1}{2} \frac{d [N O_{2}]}{d^{+}} = - 2 \frac{d [O_{2}]}{d t} = + \frac{d [N_{2} O_{5}]}{d t}$
given $\frac{- d [N O_{2}]}{d^{+}} = x$
Rate w.r.t $[N O_{2}]$ is = $\frac{x}{2}$
Rate w.r.t $O_{2} = \frac{x}{2}$
Rate w.r.t $N_{2} O_{5} = \frac{x}{2}$