$2\mathit{PbO}\left(s\right)+C\left(s\right) \to 2\mathit{Pb}\left(s\right)+C{O}_2\left(g\right)$

Which of the following statement(s) is/are correct for the above chemical reaction?

Lead is reduced is the correct statement for the given chemical reaction.
$2\mathit{PbO}\left(s\right)+C\left(s\right) \to 2\mathit{Pb}\left(s\right)+C{O}_2\left(g\right)$
C is oxidized from 0 to +4 and Pb is reduced from +2 to 0.
Initial oxidation state: $\mathit{Pb}=+2$ (bonded to ‘o’),$\mathit{ O}=-2$(normally has -2), $C=0$( is pure elemental state). 
Final oxidation state: $\mathit{Pb}=0$(pure elemental state), $O=-2$, $C=+4$(bonded to ‘O’).