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2q and 3q are two charges separated by a distance 12 cm on x-axis. A third charge q is placed at 5 cm on y-axis as shown in figure. Find the change in potential energy of the system if 3q is moved from initial position to a point on X-axis in circular path:

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$\frac{q^{2}}{4 {πε}_{o}}$

$\frac{6 q^{2}}{4 {πε}_{o} (91)}$

$\frac{18 q^{2}}{4 {πε}_{o} (91)}$

$\frac{3 q^{2}}{4 {πε}_{o}}$

answer is C.

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Detailed Solution

$ΔU = U_{f -} U_{i} and U = \frac{1}{4 {πε}_{0}} \frac{q_{1} q_{2}}{r}$

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