2Se2Cl2 SeCl4 +3Se Ew of Se2Cl2 is

Total decrease in Total increase in ox.state/mole = 2x3=6 ox.state/mole = 1x2=2 EW = M/6 EW = M/2 Alternate method Total increase in ox.state/ 2 moles = 3 Total decrease in ox.state/ 2 moles = 3

2Se2Cl2 SeCl4 +3Se Ew of Se2Cl2 is

Total decrease in Total increase in ox.state/mole = 2x3=6 ox.state/mole = 1x2=2 EW = M/6 EW = M/2 Alternate method Total increase in ox.state/ 2 moles = 3 Total decrease in ox.state/ 2 moles = 3

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

2Se₂Cl₂SeCl₄ +3Se Ew of Se₂Cl₂ is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

2M/3

4M/3

M/8

M/4

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$\begin{array}{l} \mathop {S{e_2}}\limits^{ + 1} C{l_2} \to \mathop {Se}\limits^{ + 4} C{l_4} + 3\mathop {Se}\limits^0 \\\\ \underline {S{e_2}C{l_2}(Oxidant)} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\underline {S{e_2}C{l_2}({\mathop{\rm Re}\nolimits} ductant)} \\ \,\mathop {S{e_2}}\limits^{ + 1} C{l_2} \to \mathop {Se}\limits^0 \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\mathop {S{e_2}}\limits^{ + 1} C{l_2} \to \mathop {Se}\limits^{ + 4} C{l_4} \end{array}$