$$\begin{gathered} 2\times \mathrm{sulphuric} \mathrm{acid}-{\mathrm{H}}_2\mathrm{O}+\mathrm{O}\to \mathrm{X} \\ 2\times \mathrm{sulphurous} \mathrm{acid}-{\mathrm{H}}_2\mathrm{O}=\mathrm{Y} \end{gathered}$$

Which option is the correct for the above information?

Compound forms when 2 moles of sulphuric acid is added followed by the removal of a water molecule and then the addition of one oxygen atom is H₂S₂O₈.

$2{\mathrm{H}}_2{\mathrm{SO}}_4\stackrel{-{\mathrm{H}}_2\mathrm{O}}{\to }{\mathrm{H}}_2{\mathrm{S}}_2{\mathrm{O}}_7\stackrel{\left[\mathrm{O}\right]}{\to }\underset{\left(\mathrm{X}\right)}{{\mathrm{H}}_2{\mathrm{S}}_2{\mathrm{O}}_8}$

Structure of compound X is:

Compound forms when 2 moles of sulphurous acid is added followed by the removal of a water molecule is H₂S₂O₅.

$2{\mathrm{H}}_2{\mathrm{SO}}_3\stackrel{-{\mathrm{H}}_2\mathrm{O}}{\to }\underset{\left(\mathrm{Y}\right)}{{\mathrm{H}}_2{\mathrm{S}}_2{\mathrm{O}}_5}$

Structure of compound Y is: