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Q.

2x12+5x9(x5+x3+1)3dx=

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a

x102(x5+x3+3)2+c

b

x102(3x5+x3+1)2+c

c

x102(x5+x3+1)2+c

d

x102(x4+2x3+1)2+c

answer is C.

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Detailed Solution

2x12+5x9x15(1+1x2+1x5)3dx

=(2x3+5x6)(1+1x2+1x5)3dx

[Lett=1+1x2+1x5dt=(2x35x6)dx]

t3dt=t22+c=12[1+1x2+1x5]2

=12[x10(x5+x3+1)2]+c .

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