$2x^2+y^2+2z^2-8x+2y-2xy+2xz-16z+35=0.$

Match each entry in List-I to the correct entries in List –II.

	Column-I		Column-II
P)	$x-y=$	1)	0
Q)	$x+z=$	2)	1
R)	$z=$	3)	3
S)	$x+y+z=$	4)	5
		5)	2

The correct option is

 $\Rightarrow {(x-y)}^2+{(x+z)}^2+z^2-16z-8x+2y+35=0$
 $\Rightarrow {(x-y-1)}^2+{(x+z-3)}^2+z^2-10z-+25=0$ 
 $\Rightarrow {(x-y-1)}^2+{(x+z-3)}^2+{(z-5)}^2=0$  
  Thus, $x-y=1,x+z=3,z=5$ and hence, $x=-2,y=-3.$
   Thus, the solution is $x=-2,y=-3$ and $z=5.$