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Q.

(2x3+4x23x3+2x)dx=

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a

23x3+4x+32x22logx+c

b

23x34x+32x2+2logx+c

c

23x34x32x22logx+c

d

23x3+4x+32x2+2logx+c

answer is B.

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Detailed Solution

(2x3+4x23x3+2x)dx

=2x3+4x23x3+2x

=2x4+4x23x3+21x

=2(x4+14+1)+4(x2+12+1)3(x3+13+1)+2logx+c

=2x33+4(x1)13(x2)2+2logx+c

=23x34x+32x2+2logx+c

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