3 - Hydroxy butanal is formed when (X) reacts with (Y) in dilute (Z) solution. X, Y, Z are:

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$X = C H_{3} C H O$ $Y = (C H_{3})_{2} C O$ $Z = N a O H$

$X = C H_{3} C H O$ $Y = C H_{3} C H O$ $Z = N a C l$

$X = (C H_{3})_{2} C O$ $Y = (C H_{3})_{2} C O$ $Z = H C l$

$X = C H_{3} C H O$ $Y = C H_{3} C H O$ $Z = N a O H$

answer is D.

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Detailed Solution

Aldol condensation: When a base (NaOH) is present, the aldol condensation of two acetaldehyde molecules results in the formation of 3-hydroxy butanal.

Hence, the correct option is (D) $C H_{3} C H O$ $C H_{3} C H O$ $N a O H$

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