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Q.

3.6 g of an ideal gas was injected into a bulb of internal volume of 8 L  at P atm pressure   and temp T K. The bulb was then placed in a thermostat maintained at  (T+15)K. 0.6 g of the gas was let-off to keep the original pressure. If initial temperature of gas is 

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answer is 75.

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Detailed Solution

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Using the relative  pV=nRT
 P×8=(3.6M)(R)(T) P×8=(3M)(R)(T+15)
 On solving,  T=75K

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