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-3 and 4 are the zeroes of a quadratic polynomial

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x 2 − x + 12

x 2 + x + 12

x 2 2 − x 2 − 6

2 x 2 + 2 x − 24

answer is C.

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Detailed Solution

It is given that -3 and 4 are the zeroes of a quadratic polynomial.
We know that,

x 2 −

(sum of zeroes)

x +

(product of zeroes) = 0 … (1)
Then, Now, we will obtain the sum and product of the zeroes.

Sum of zeroes = - 3 + 4 = 1

And

Product of zeroes = (- 3) (4) = - 12

Now, we will substitute the sum of zeroes and the product of zeroes in equation (1),

x^{2} - x - 12 = 0

On dividing the above equation by 2, we get,

⇒ x 2 2 − x 2 − 6 = 0

Therefore, option 3 is correct.

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