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Q.

3 and 6 electrons are present in the outermost orbit of A and B respectively. The chemical formula of its compound will be

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a

$A_{3} B_{2}$

b

$A_{2} B_{3}$

c

$A_{2} B$

d

AB

answer is B.

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Detailed Solution

$A_{2} B_{3}$

$A \overset{- 3 e^{-}}{\to} A^{+ 3}; B \overset{+ 2 e^{-}}{\to} B^{- 2}$

Since valence of A = 3 ,

Valence of B=8-6=2 .

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