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Q.

3 g of activated charcoal was added to 50 mL of acetic acid solution (0.06 N) in a flask. After an hour it was filtered and the strength of the filtrate was found so be 0.042 N. The amount of acetic acid adsorbed (per gram of charcoal) is

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a

18 mg

b

36 mg

c

42 mg

d

54 mg

answer is D.

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Detailed Solution

Given, initial strength of acetic acid = 0.06 N

Final strength = 0.042N, volume given = 50 mL

 Initial millimoles of CH3COOH=0.06×50=3

 Final millimoles of CH3COOH=0.042×50=2.1

 Millimoles of CH3COOH adsorbed =3-2.1=0.9mmol

                                                            = 0.9x60 mg

                                                            = 54 mg

 

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