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3 molecules of ${CO}_{2} weighs$

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$44 \times 10^{- 23} g$

$33 \times 10^{- 23} g$

$11 \times 10^{- 23} g$

$22 \times 10^{- 23} g$

answer is D.

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Detailed Solution

1 Mole ${CO}_{2} = 6 \times 10^{23} molecles of {CO}_{2}$

We know that $6 \times 10^{23} molecles of {CO}_{2} has 44 g of {CO}_{2}$

3 molecules ${CO}_{2} \to ? g of {CO}_{2}$

Then weigh of ${CO}_{2}$ in 3 molecules,

$\frac{44 g}{6 \times 10^{23} molecules of {CO}_{2}} \times 3 m o l e c u l e s C O_{2} = 22 \times 10^{- 23} g$

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