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Q.

3 moles of an ideal monoatomic gas performs ABCDA cyclic process as shown in figure below. The gas temperatures are TA=400K,TB=800K,TC=2400KandTD=1200K. The work done by the gas is (approximately) (R=8.314 J/mole K)

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a

100 kJ

b

20 kJ 

c

40 kJ

d

10 kJ

answer is B.

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Detailed Solution

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For process AB=W=0 

For process BC=W=nRΔT=3×R[2400−800]

=3R×1600=4800R

For process CD = W=0 

For process DA=W=3R[400−1200]=−2400R 

Total work = 2400R=2400×253=800×25=20kJ

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