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Q.

3 moles of gas "X" and 2 moles of gas "Y enters from end "P" and "Q" of the cylinder respectively. The cylinder has the area of cross-section A, shown as under -
The length of the cylinder is 150 cm. The gas "X" intermixes with gas "Y" at the point A. If the molecular weight of the gases X and Y is 20 and 80 respectively, then what will be the distance of point A from Q?

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a

50 cm

b

90 cm

c

75 cm

d

37.5 cm

answer is B.

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Detailed Solution

$\frac{r_{x}}{r_{y}}$ = $\frac{n_{x}}{n_{y}} \sqrt{\frac{M_{y}}{M_{x}}}$ = $\frac{3}{2} \sqrt{\frac{80}{20}}$ = $\frac{3}{1}$ =3:1
∴ $\frac{distance travelled by gas X}{distance travelled by gas Y}$ =3:1
∴distance of A from Q= $\frac{150}{3}$ =50cm

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