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Q.

3. The value of the expression,cosec (75° + θ)  sec (15°  θ)  tan (55° + θ) + cot (35°  θ) is ____.

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a

2

b

-1

c

0

d

3

answer is C.

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Detailed Solution

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According to the question,

We have to find the value of the equation,

cosec(75°+θ)  sec(15°-θ)  tan(55°+θ) + cot(35°-θ)

=cosec[90°-(15°-θ)]  sec(15°-θ)  tan(55°+θ) + cot[90°-(55°+θ)]

Since, cosec (90°- θ) = sec θ

And, cot(90°-θ) = tan θ

We get,

sec(15°-θ)  sec(15°-θ)  tan(55°+θ) + tan(55°+θ)

=0

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