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Q.

30 lit of oxygen is liberated at STP by the complete decomposition of a sample of 1 lit of H₂O₂. The molarity of that H₂O₂ solution is nearly

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a

0.893 M

b

1.785 M

c

2.678 M

d

3.572 M

answer is C.

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Detailed Solution

1 lit of H₂O₂ solution

\xrightarrow{{\;\;\Pr oduces\;\;}}\;

30lit of "O₂"

i.e.. The volume strength of the H₂O₂ solution is 30vol strength.

\\\\Molarity\;=\;\frac{volume\;strength}{11.2}\\\\M\;=\;\frac{30}{11.2}\;=\;2.678M

(OR)
2H₂O₂ → 2H₂O + O₂
2 x 34gr ------22.4 lit
?? -------30lit

\frac{30\times 2\times 34}{22.4}\;=\;91.078gr[W/V%]

\\\\M\;=\;\frac{Wt}{MW}\;\times\;\frac{1}{V(in\;lit)}\\\\M\;=\;\frac{91.07}{34}\;\times \;\frac{1}{1}

M = 2.678M

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