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Q.

300 J of work is done in sliding a 2 kg block up an inclined plane of height 10 m. Taking g = 10m/s2, work done against friction is :

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a

zero

b

100 J

c

200 J

d

1000 J

answer is B.

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Detailed Solution

By Work-Energy Theorem W=ΔKE
We have 300 - Wgravity - Wfriction = 0 - 0
Wfriction = 300 - mgh = 300-200 = 100 J

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